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[" 1"6x" a(b+c) "],[" 1"],[" ad "b(c+a)]...

[" 1"6x" a(b+c) "],[" 1"],[" ad "b(c+a)],[" 1ab "c(a+b)]

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|[1,bc,a(b+c)],[1,ca,b(c+a)],[1,ab,c(a+b)]|=0

Without expanding, prove that : |{:(1, bc, a(b+ c) ),(1, ca, b ( c+ a) ),(1, ab , c( a+ b)):}|=0 .

Prove the following : [[1,bc,a(b+c)],[1,ca,b(c+a)],[1,ab,c(a+b)]] =0

|[bc, b+c, 1], [ca, c+a, 1], [ab, a+b, 1]|=?

|(1,bc,a(b+c)),(1,ca,b(c+a)),(1,ab,c(a+b))|=

|(1,bc,a(b+c)),(1,ca,b(c+a)),(1,ab,c(a+b))|= 0

|{:(1,bc,a(b+c)),(1,ca,b(c+a)),(1,ab,c(a+b)):}|=0

If A=|[1, 1, 1],[a, b, c],[ a^2,b^2,c^2]| , B=|[1,bc, a],[1,ca, b],[1,ab, c]| , then

|[1,a, bc] ,[1, b, ca], [1, c, ab]| = (a-b)(b-c)(c-a)