If the two circles `2x^2+2y^2-3x+6y+k=0` and `x^2+y^2-4x+10 y+16=0` cut orthogonally, then find the value of `k` .

If the two circles 2x^(2)+2y^(2)-3x+6y+k=0 and x^(2)+y^(2)-4x+10y+16=0 cut orthogonally,then find the value of k .

If the two circles 2x^(2) +2y^(2) -3x+6y+k=0 and x^(2) +y^(2) -4x +10y +16=0 cut orthogonally, then the vlaue of k is-

If the circles x^(2)+y^(2)-2 x-2 y-7=0 and x^(2)+y^(2)+4 x+2 y+k=0 cut orthogonally, then the length of the common chord of the circles is

The circles x^2+y^2-6x-8y+12=0, x^2+y^2-4x+6y+k=0 , cut orthogonally then k=

The circles x^2+y^2-6x-8y+12=0, x^2+y^2-4x+6y+k=0 , cut orthogonally then k=

If the circles x^(2) + y^(2) - 6x - 8y + 12 = 0 , x^(2) + y^(2) - 4x + 6y + k = 0 cut orthogonally, then k =

If the two circle x^(2) + y^(2) - 10 x - 14y + k = 0 and x^(2) + y^(2) - 4x - 6y + 4 = 0 are orthogonal , find k.

For the circles x^2 + y^2 - 2x + 3y + k = 0 and x^2 + y^2 + 8x - 6y - 7 = 0 to cut each other orthogonally the value of k must be