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If f(m) = sum(i=0)^m ((30),(30-i)) ((20)...

If `f(m) = sum_(i=0)^m ((30),(30-i)) ((20),(m-i))` where `((p),(q)) = pCq,` then (A) maximum value of f(m) is 50C 25 (B) `f(0)+f(1) +...+f(50) =2^50` (C) f(m) is always divisible by 50 (`1<=m<=49`) (D)`sum_(m=0)^(50) (f(m))^2=100C50`

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