[2y-3z=0],[x+3y=-4],[3x+4y=3]

Solve the following by Cramer's rule : 2y-3z=0, x+2y+4=0, 3x+4z-3=0

The area of the parallelogram formed by the lines 4y-3x-a=0, 3y-4x+a=0, 4y-3x-3a=0, 3y-4x+2a=0 is

Using matrices, solve the following system of equations for x,y and z. 2x+3y+3z=5 , x-2y+z=-4 , 3x-y-2z=3

The system of equations {:(x+2y+3z=4),(2x+3y+4z=5),(3x+4y+5z=6):} has …………… solutions

Add the following expressions: 2x+9y-7z, 3y+z-3x, 3z-4y-x

2x+3y+3z=5 x-2y+z=-4 3x-y-2z=3

2x-y+z=6,x+2y+3z=3,3x+y-z=4

Find the nature of solution for the given system of equation: x+2y+3z=1;2x+3y+4z=3;3x+4y+5z=0

Find the nature of solution for the given system of equation: x+2y+3z=1;2x+3y+4z=3;3x+4y+5z=0