Two particles of mass m and M are initially at rest and infinitely separated from each other. Due to mutual interaction, they approach each other.
Their relative velocity of approach at a separation d between them, is

Two bodies of masses m_1 and m_2 are initially at rest and infinite distance apart. Due to mutual attraction, they approach each other. When they are r distance apart, their relative velocity of approach is

Two particles of masses m_(1) and m_(2) initially at rest a infinite distance from each other, move under the action of mutual gravitational pull. Show that at any instant therir relative velocity of approach is sqrt(2G(m_(1)+m_(2))//R) where R is their separation at that instant.

Two bodies of mass m_(1) and m_(2) are initially at rest placed infinite distance apart. They are then allowed to move towards each other under mutual gravitational attaction. Show that their relative velocity of approach at separation r betweeen them is v=sqrt(2G(m_(1)+m_(2)))/(r)

Two bodies of mass m_(1) and m_(2) are initially at rest placed infinite distance apart. They are then allowed to move towards each other under mutual gravitational attaction. Show that their relative velocity of approach at separation r betweeen them is v=sqrt(2G(m_(1)+m_(2)))/(r)

Two particles of mass 'm' and 3 m are initially at rest an infinite distance apart. Both the particles start moving due to gravitational attraction. At any instant their relative velocity of approach is sqrt((ne Gm)/d where 'd' is their separation at that instant. Find ne.