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Three cubes of iron whose edges are 6 cm...

Three cubes of iron whose edges are 6 cm, 8 cm and 10 cm respectively formed into a single cube. The edge of the new cube is

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sum of volume of cubes = vol of new cube
`(6)^3 + (8)^3 + (10)^3 = a^3 `
`a^3 = 216 + 512 + 1000`
`a^3 = 1728`
`a = (1728)^(1/3)`
`a = 12`cm
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