The angle between the two lines `1x+my+n=0` and `1'x+m'y+n'=0` is given by `tan^(-1) theta`. What `theta` equal to ?

If the angle between the lines sqrt(3)y-x+4=0 and x+y-6=0 is theta , then tan theta is equal to.

If the angle between the curves x^(2)y=1 and y=e^(2(1-x)) at the point (1,1) is theta, then tan theta is equal to

If the angle between the two lines y^(2)+kxy-x^(2)tan^(2) theta=0 is 2 theta then k=

If (theta) is an acute angle between the lines y=2x+3,y=x+1 then the value of tan theta=

A : If the angle between the lines kx-y+6=0, 3x+5y+7=0 is pi//4 one value of k is 4 R : If theta is angle between the lines with slopes m_(1), m_(2) then tan theta=(|m_(1)-m_(2)|)/(|1+m_(1)m_(2)|) .

If theta is the angle between the lines x//a+y//b=1, x//b+y//a=1 , then cos theta=

If the point (1+cos theta,sin theta) lies between the region corresponding to the acute angle between the lines 3y=x&6y=x and a