If the distances of the vertices of a triangle =ABC from the points of contacts of the incercle with sides are `alpha,betaa n dgamma` then prove that `r^2=(alphabetagamma)/(alpha=beta+gamma)`

If the distances of the vertices of a triangle =ABC from the points of contacts of the incercle with sides are alpha,beta and gamma then prove that r^(2)=(alpha beta gamma)/(alpha=beta+gamma)

If the distances of the vertices of a triangle from the point of contact of the incricle with the sides be alpha,beta,gamma then r is equal to (where r=inradius)

In a Delta ABC, D,E and F respectively are the points of contact of the incircle with the sides AB, BC and CA such that AD =alpha, BE= beta and CF =gamma," then "(alpha beta gamma)/(alpha +beta +gamma)=

If alpha , beta, gamma are the lengths of the tangents from the vertices of a triangle to its incircle. Then

If alpha,betaa n dgamma are the roots of x^3+8=0 then find the equation whose roots are alpha^2,beta^2a n dgamma^2 .

If alpha,betaa n dgamma are the roots of x^3+8=0 then find the equation whose roots are alpha^2,beta^2a n dgamma^2 .

If alpha,betaa n dgamma are the roots of x^3+8=0 then find the equation whose roots are alpha^2,beta^2a n dgamma^2 .

A line makes angles alpha,betaa n dgamma with the coordinate axes. If alpha+beta=90^0, then find gammadot