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Five digit number divisible by 3 is form...

Five digit number divisible by 3 is formed using 0 1 2 3 4 6 and 7 without repetition Total number of such numbers are

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`0,1,2,3,4,6,7`
sum = `23`
`23 -> 2 -> 21, 2[0,2]`
`-> 5 -> 18, 5[2,3], [1,4]`
`-> 8 -> 15, 8[7,1], [6,2]`
`-> 11 -> 12, 11[7,4]`
`0,2 : 1 , 3,4,6,7 : 120`
`2,3 : 0, 1,4 ,6,7 : 96`
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