The force on a particle of mass 10 g is `(veci10 + vecj5)N`. If it starts from rest what would be its position at time `t=5s?

The force on a particle of mass 10g is (hati 10+hatj 5) N If it starts from rest what would be its position at time t=5s ?

The force on a particle of mass 10g is (hati 10+hatj 5) N If it starts from rest what would be its position at time t=5s ?

The force on a particle of mass 10 g is (10 hat(i) + 5 hat(j)) N. If it starts from rest what would be its position at time t = 5s ?

A time dependent force F = 6t acts on a particle of mass 1 kg. If the particle starts from rest, the work done by the force during the first 1 s will be

A force vec(F) = (40 hat (i) + 10 hat(j)) N acts on body of mass 5 kg. If the body starts from rest, its position vector vec(r) at time t = 10 s, will be

A force of 10 N acts on a body of mass 0.5 kg for 0.25s starting from rest.What is its momentum now?

A force of 10 N acts on a body of mass 0.5 kg for 0.25s starting from rest.What is its momentum now?

A force of 200 dyne acts on a body of mass 10 g for 5 s. What will be the velocity of the body if it starts from rest ? Express in SI unit .

A particle initially at rest starts moving along x-axis.Its acceleration varies with time as a=6tm/s^(2) .If it starts from x=10m .Then the position of particle at t=2s is