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If Arg((z-1)/(z+1))= pi/2 then the locus...

If `Arg((z-1)/(z+1))= pi/2` then the locus of z is `) circle with radius 2 2) circle with radius 1 3) straight line 4) pair of lines

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`arg ( z_1/z_2) = theta`
`arg z_1 - arg z_2 = theta`
`ar((z-1)/(z+1)) = pi/2`
`arg(z +1) = theta`
`arg(z-1) = pi/2 + theta`
in `/_ ZAB`
`/_ AZB = 180^@ - /_A - /_B`
`= 180^@ - theta - pi/2 + theta`
...
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