Urea`(H_(2)NCONH_(2))` is manufactured by passing `CO_(2)`(g) through ammonia solution followed by crystallization. For the above reaction is prepared by combustion of hydrocarbons. If combustion of 236 kg of a saturated hydrocarbon `(C_(n)H_(2n+2))` produces as much `CO_(2)` as required for production of 999.6 kg urea then molecular formula of hydrocarbon is:

Urea (H_(2)NCONH_(2)) is manufactured by passing CO_(2) (g) through ammonia solution followed by crystallization. CO_(2) for the above reaction is prepared by combustion of hydrocarbon. If combustion of 236kg of a saturated hydrocarbon (C_(n)H_(2n+2)) produces as much CO_(2) as required for production of 999.6 kg urea then molecular formula of hydrocarbon is : C_(10)H_(22) , C_(12)H_(26) , C_(13)H_(28) , C_(8)H_(18) ,

Urea (H_2NCONH_2) is manufactured by passing CO_2(g) through ammonia solution followed by crystallization. CO_2 for the above reaction is prepared by combustion of hydrocarbons. If combustion of 236kg of a saturated hydrocarbon (C_n H_(2n+2)) produces as much CO_2 as required for production of 999.6kg urea then molecular formula of hydrocarbon is :

Define saturated hydrocarbon and explain that C_2H_6 is a saturated hydrocarbon.

1 litre of a hydrocarbon weight as much as one litre of CO_(2) . The molecular formula of hydrocarbon is :-

11.2 litre of a hydrocarbon at STP produces 44.8 litre of CO_(2) at STP and 36 gm of H_(2)O during its combustion. Calculate the molecular formula of hydrocarbon.

11.2 litre of a hydrocarbon at STP produces 44.8 litre of CO_(2) at STP and 36 gm of H_(2)O during its combustion. Calculate the molecular formula of hydrocarbon.

10 mL of a certain hydrocarbon require 25 mL of oxygen for complete combustion and the volume CO_(2) of product is 20 mL. What is the formula of hydrocarbon ?