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[" 32.fiter and- "],[qquad [[1+a,1,1],[1...

[" 32.fiter and- "],[qquad [[1+a,1,1],[1,1+b,1],[1,1,1+c]]=abc(1+(1)/(a)+(1)/(b)+(1)/(c))]

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det[[ Prove ,1,11,1+b,11,1,1+c]]=abc((1)/(a)+(1)/(b)+(1)/(c)+1)

Prove that : Det[[1+a,1,1],[1,1+b,1],[1,1,1+c]]=abc(1+1/a+1/b+1/c)

det[[ Show that ,11+a,1+b,11,1+b,11,1,1+c]]=abc(1+(1)/(a)+(1)/(b)+(1)/(c))

Prove that |(1+a,1,1),(1,1+b,1),(1,1,1+c)|=abc(1+(1)/(a)+(1)/(b)+(1)/(c)).

det[[ Show that ,1+a,1,11,1+b,11,1,1+c]]=abc(1+(1)/(a)+(1)/(b)+(1)/(c))=abc+bc+ca+ab

Prove that |{:(1+a,1,1),(1,1+b,1),(1,1,1+c):}| =abc (1+(1)/(a)+(1)/(b)+(1)/(c))

Prove that |{:(1+a,1,1),(1,1+b,1),(1,1,1+c):}| =abc (1+(1)/(a)+(1)/(b)+(1)/(c))

Using properties of determinants show that abs[[1+a,1,1],[1,1+b,1],[1,1,1+c]]=abc(1+1/a+1/b+1/c)

Show that Determinant of [[1+a,1,1],[1,1+b,1],[1,1,1+c]] = abc (1+1/a+1/b+1/c)

Show that {:[( 1+a,1,1),( 1,1+b,1) ,( 1,1,1+c) ]:}= abc ( 1+(1)/(a) +(1)/(b) +(1)/(c) ) = abc +bc +ca +ab