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[" 1."sin40^(@)25^(1)cos19^(@)35^(1)+cos...

[" 1."sin40^(@)25^(1)cos19^(@)35^(1)+cos40^(@)25^(1)*sin19^(@)35^(1)=],[[" 1) "1," 2) "(sqrt(3))/(2)," 3) "0," 4) "-1]]

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sin40^(@)35'cos19^(@)25'+cos40^(@)35'sin19^(@)25 is equal to

sin(40^@25')cos(19^@35')+cos(40^@25')sin(19^@35')=

sin25^(@)cos115^(@)=(1)/(2)(sin40^(@)-1)

cos^(2)25^(@)+cos^(2)35^(@)-cos25^(@) cos35^(@)=

cos20^(@)cos40^(@)-sin5^(@)sin25^(@)=

(cos20^(@)35')/(sin69^(@)25') is

Evaluate : sin50^(@)cos40^(@)+cos40^(@)+cos50^(@)sin40^(@)

Evaluate : sin50^(@)cos40^(@)+cos40^(@)+cos50^(@)sin40^(@)

(sin70^(@)+cos40^(@))/(cos70^(@)+sin40^(@))

(sin70^(@)+cos40^(@))/(cos70^(@)+sin40^(@))=?