An object has an excess charge of `(-1.92xx10^(10-7)) C`. How many excess electrons does it have ?

Explanation

To find the number of excess electrons in an object with a given excess charge, we can use the formula that relates charge (Q), number of electrons (N), and the charge of a single electron (e):

### Step-by-Step Solution:

1. **Identify the given charge**:
The excess charge of the object is given as:
\[
Q = -1.92 \times 10^{-17} \, \text{C}
...