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A free pith ball p of 10g carries of 5x...

A free pith ball p of 10g carries of `5xx10^(-8) C`. What must be the nature and maganitude fo charge that should be given to another pith ball Q fixed 7 cm below the former ball, so that upper ball is statinary ?

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To solve the problem, we need to find the charge that should be given to the fixed pith ball Q so that the free pith ball P remains stationary. Here are the steps to arrive at the solution: ### Step-by-Step Solution: 1. **Identify the Given Values:** - Mass of ball P, \( m = 10 \, \text{g} = 0.01 \, \text{kg} \) (convert grams to kilograms) - Charge on ball P, \( Q_1 = 5 \times 10^{-8} \, \text{C} \) - Distance between the two balls, \( R = 7 \, \text{cm} = 0.07 \, \text{m} \) (convert centimeters to meters) ...
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