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A particle of mass `m` and carrying charge `-q_(1)` is moving around a charge `+q_(2)` along a circular path of radius `r` period of revolution of the charge `-q_(1)` about `+q_(2)` is

Text Solution

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Here, force of attraction between charges = centripetal force
`(1)/(4pi in_(0)) (q_(1) q_(2))/(r^(2)) = (mv^(2))/(r)`
So `v = sqrt((1)/(4pi in_(0)) (q_(1) q_(2))/(mr)`
Time period of revolution
`T = (2pi r)/(v) = (2pi r) sqrt((4pi in_(0) mr)/(q_(1) q_(2)))`
`T = sqrt((16pi^(3) in_(0) mr^(3))/(q_(1) q_(2)))`
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