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A particle of mass 10^(-4) kg and charge...

A particle of mass `10^(-4) kg` and charge `5muC` id thrown at a speed of `20m//s` against a uniform electric field of strength `2xx10^(5) NC^(-1)`. How much distance will it travel before coming to rest momentarily?

Text Solution

Verified by Experts

Here, `m = 10^(-4) kg ,`
`q = 5 muC = 5xx10^(-6) C , v = 20 ms^(-1),`
`E = 2xx10^(5) N//C`
Force on charged particle
`F = qE = 5xx10^(-6)xx2xx10^(5) = 1N`
As particle is thrown against the field, so
`a = - (F)/(m) = - (1)/(10^(-4)) = - 10^(4) m//s^(2)`
From `v^(2) - u^(2) = 2as`
`:. (0)^(2) -(20)^(2) = 2 (-10^(4))s`
`:. s = 0*023m`
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