A charged particle of charge `2 muC` and mass `10` milligram, moving with a velocity of `1000 m//s` enters a uniform electric field of strength `10^(3) N//C` directed perpendicular to its direction of motion. Find the velocity and displacement of the particle after `10s`.

Explanation

To solve the problem step by step, we will analyze the motion of the charged particle in the electric field and calculate both its velocity and displacement after 10 seconds.

### Step 1: Identify the given values
- Charge of the particle, \( q = 2 \, \mu C = 2 \times 10^{-6} \, C \)
- Mass of the particle, \( m = 10 \, mg = 10 \times 10^{-6} \, kg = 10^{-5} \, kg \)
- Initial velocity, \( u_x = 1000 \, m/s \) (in the x-direction)
- Electric field strength, \( E = 10^3 \, N/C \) (in the y-direction)
- Time, \( t = 10 \, s \)
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