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Two charges +- 10 muC are placed 5xx10^(...

Two charges `+- 10 muC` are placed `5xx10^(-3) m` apart. Determine the electric field at a point `Q, 0*15m` away from O, on a line passing through O and normal to the axis of the diople.

Text Solution

Verified by Experts

Here, `q = +- 10 muC = +- 10xx10^(-6) C`,
`2a = 5xx10^(-3) m, r = 0*15m`
The point Q lies on equatorial line of electric dipole,
`As r gt gt` a So, `E = (p)/(4pi in_(0) r^(3)) = (q(2a))/(4pi in_(0) r^(3))`
`E = (9xx10^(9)xx10xx10^(-6)xx5xx10^(-3))/((0*15)^(3))`
`= 1*33xx10^(5) NC^(-1)`
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