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Figure shows the electirc field lines f...

Figure shows the electirc field lines for two point charges separated by a distance. What are the signs of `q_(1) and q_(2)` ? Can you determine the ratio `q_(1)|q_(2)` ?

Text Solution

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As the electric field lines emmante from `q_(1)` and some of them end at `q_(2)`, therefore `q_(1)` , must be a positive charge and `q_(2)` must be a negative charge. As the number of lines leaving `q_(1)` is twice the number of field lines terminating on `q_(2)`, therefore, magnitude of `q_(2), i.e., q_(1)|q_(2) = 2.`
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Knowledge Check

  • Two point charges Q and - Q //4 are separated by a distance X . Then .

    A
    potential is zero at a point on the axis which is ` x//3` on the right side of the cahrge `-q//4`
    B
    potential is zero at a point on the axis which is `x//5` on the left side fo the charge `- Q//4`
    C
    electric field is zero at a point on the axis which is at a distance `x` on the right side fo the charge `- Q//4`
    D
    there exist two points on the axis where electric field is zero.

  • In the adjoining figure, the electric field lines for charges q_1 and q_2 are shown. Identify the sign of the charges.

    A
    both negative
    B
    upper charge is negatively and lower is positive
    C
    both positive
    D
    upper charge is positive and lower is negative

  • Magnitude of force between two point charges q_1 and q_2 which are separated by a distance r is given by

    A
    `F=(k|q_1q_2|)/r`
    B
    `F=(k|q_1q_2|r)/r^2`
    C
    `F=k((|q_1q_2|)/r)^2`
    D
    `F=(k|q_1q_2|)/r^2`

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