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A charge of 17*7xx10^(-4)C is distribu...

A charge of `17*7xx10^(-4)C` is distributed over a large sheet of area `400 m^(2)`. Calculate the electric field intensity at a distance of `10 cm` from it.

Text Solution

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Here `q = 17*7xx10^(-4) C, A = 400 m^(2), E = ?, r = 10 cm , 10^(-1) m`
In case of a large plane sheet, distance of the point `(=r)` does not manner.
`E = (sigma)/(2 in_(0)) = (q//A)/(2in_(0)) = (q)/(2in_(0) A) = (1*77xx10^(-4))/(2xx(8*85xx10^(-12))xx400) = 2*5xx10^(5) N//C`
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