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Consider a uniform electric field E = 3...

Consider a uniform electric field `E = 3xx10^(3) hat(i) N//C`. (a) What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane ? (b) What is the flux through the same square if the normal to its plane makes a `60^(@)` angle with the x-axis ?

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Here `E = 3xx10^(3) hat(i) NC^(-1)`:
`A = (0.1 m)^(2) = 10^(-2)m^(2)`
(i) As normal to area is in the direction of electric field, therefore, `theta = 0^(@)`
`phi' = EA cos theta = 3xx10^(3)xx10^(-2) cos 0^(@)`
`= 30 Nm^(2) C^(-1)`
(ii) In this case, `theta = 60^(@)`
`:. phi' = EA cos theta = 3xx10^(3)xx10^(-2) cos 60^(@)`
`= 15 Nm^(2) C^(-1)`
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