The electric field componets due to a charge inside the cube of side 0.1m are `E_(x) = alpha x,` where `alpha = 500 (N//C) m^(-1)`,
`E_(y) = 0, E_(z) = 0`. Calculate the flux through the cube and the charge inside the cube.

Explanation

To solve the given problem, we need to calculate the electric flux through the cube and the charge inside the cube. Let's break down the solution step by step.

### Step 1: Calculate the Electric Flux through the Left Face of the Cube
The electric field component in the x-direction is given by \( E_x = \alpha x \), where \( \alpha = 500 \, \text{N/C} \cdot \text{m}^{-1} \).

1. **Determine the area vector for the left face:**
- The left face of the cube is at \( x = 0 \).
- The area vector \( \vec{A} \) for the left face points in the negative x-direction.
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