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Define an equipotential surface. Draw eq...

Define an equipotential surface. Draw equipotential surfaces :
`(i)` in the case of single point charge and
`(ii)` in a constant electric field in `Z`-direction.
Why the equipotential surfaces about a single charge are not equidistant ?
`(iii)` Can electric field exist tangential to an equipotential surface ? Given reason.

Text Solution

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(i) An equipotential surface is that at every point of which electric potential is the same. Due to a single point charge, equipotnetial surfaces are centred at the
charge, As `V prop (1)/(r )`, the equipotential surfaces
about a single charge cannot be equidistant.
(ii) In a constant electric field in Z- direction, equipotential surfaces lie in XY plane perpendicular to Z-direction as shown in Fig.

(iii) As electric fied is perpendicular to the equipotential surface, the field cannot exist tangenital to the equipotential surface.
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Knowledge Check

  • The electric field lines coming out of an equipotential surface are

    A
    perpendicular to the surface
    B
    parallel to the surface
    C
    in all directions
    D
    zero
  • Nature of equipotential surface for a point charge is

    A
    ellopsoid with charge at foci
    B
    sphere with charge at the centre of the sphere
    C
    sphere with charge on the surface of the sphere
    D
    plane with charge on the surface
  • The shape of equipotential surfaces due to an isolated charge is

    A
    Concentric spherical shells and the distance between the shells increases with the decrease in electric field
    B
    Concentric spherical shells and the distance between the shells decreases with the decrease in electric field
    C
    Equi-spaced concentric spherical shells
    D
    Changes with the polarity of the charge
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