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Around a point charge of 1 nC, what is ...

Around a point charge of `1 nC`, what is the distance of an equipotential surface of `0.9V` ?

A

10 m

B

0.1 m

C

20 m

D

9 m

Text Solution

Verified by Experts

The correct Answer is:
A
Here `q = 1nC = 10^(-9) C, V = 0.9 V, r = ?`
As `V = (q)/(4pi in_(0) r)`
`:.r = (q)/(4pi in_(0) r) = (10^(-9)xx9xx10^(9))/(0.9) = 10m`
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