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A potential difference of 250 Volt is ap...

A potential difference of 250 Volt is applied across the plate of a capacitor of 10 pF. Calculate the charge on the plates of the capacitor.

Text Solution

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Here, `V = 250V , C = 10 pF = 10xx10^(-12) F = 10^(-11) F`.
`:. Q = CV = 10^(-11)xx250 = 2.5xx10^(-9)C`.
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