In fig potential difference between the points X and Y, when `C_(1) = 2 muF , C_(2) = 3 muF , C_(3) = 4 muF , C_(4) = 5 muF` and e.m.f of battery is 5 V.

Explanation

Equivatent capacity of `C_(1)` and `C_(2)` is C' ,
where `(1)/(C ) + (1)/(C_(1)) + (1)/(C_(2)) = (1)/(2) + (1)/(3) = (5)/(6) , C' = (6)/(5) muF`.
Charge on `C_(1) or C_(2) = q_(1) = C'V = (6)/(5) xx 5 = 6 muC`.
Potential difference across `C_(1) is V_(X) = (q_(1))/(C_(1)) = (6)/(2) = 3 V`.
where `(1)/(C'') = (1)/(C_(3)) + (1)/(C_(4)) = (1)/(4) + (1)/(5) = (9)/(20) , C" = (20)/(9) muF`.
Charge on `C_(3)` or `C_(4) = q_(2) = C"V = (20)/(9)xx5 = (100)/(9) muC`
Potential difference across `C_(3)` is `V_(Y) = (q_(2))/(C_(3)) = (100//9)/(4) = (25)/(9) V`.
`V_(X) - V_(Y) = 3 - (25)/(9) = (2)/(9) V = 0.22V`