Find the capacitance of the combination shown in Fig.

Explanation

Starting from the left side of network, two `2 muF` capacitors are in series. Therefore,
`(1)/(C_(s)) = (1)/(2) + (1)/(2) = 1, C_(s) = 1 muF`.
This 1 `muF` and third 1 `muF` capacitor are in parallel. Therefore,`C_(p) = 1 + = 2 muF` and so on.
Proceeding in this way, finally two `2 muF` capacitors are in series. Therefore, capacitanace of the combination between A and B is `1 mu F`.