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In the circuit shown in Fig. the key K ...

In the circuit shown in Fig. the key K was initally in contact with the teminal A. What amount of heat will be generated in `500 Omega` resitance, when the key k is brought in contact with terminal B ?

Text Solution

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When key K is in contact with terminal A, the condeser gets charged. Energy strored in condenser
`U = (1)/(2) CV^(2) = (1)/(2) (500xx10^(-6)) xx 200xx200`
= 10 joule.
When key K is brought in contact with terminal B. The centire energy stored is dissipated as heat energy.
As `500 Omega and 330 Omega` resistances are in series, heat produced is the ratio 500 : 330,
`:.` Heat produced in 500 ohm resitance
`= (500)/(500+330) xx U = (500xx10)/(830) = 6.024 J`
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