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A slab of material of dielectric constan...

A slab of material of dielectric constant K has the same area as the plates of a parallel capacitor, but has a thickness `((3)/(4) d)`,
where d is the separation of the plates. How is the capacitance changed when the slab is inserted between the plates

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To solve the problem step by step, we will analyze the situation of a parallel plate capacitor with a dielectric slab inserted between its plates. ### Step 1: Understand the initial capacitance of the capacitor The initial capacitance \( C \) of a parallel plate capacitor without any dielectric is given by the formula: \[ C = \frac{\varepsilon_0 A}{d} \] where: ...
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