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A parallel plate capacitor of plate area...

A parallel plate capacitor of plate area `(1xx3) m^(2)` and plate separation 5.0 mm is charged to 10 kV in air. Find charge density and field displacement.

Text Solution

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Here, `A = 1xx2 = 2m^(2)`
`d = 5mm = 5xx10^(-3) m`
`V = 10kV = 10^(4)V rho = ?`
field displacement = ?
`Q = CV = (in_(0) A)/(d) V = (8.85xx10^(-12)xx2)/(5xx10^(-3)) xx10^(4)`
`Q = 3.54xx10^(-5) C`
Charge density, `rho = (Q)/(A) = (3.54xx10^(-5))/(2)`
`= 1.77xx10^(-5) Cm^(-2)`
Field displacement = charge density
`= 1.77xx10^(-5) Cm^(-2)`
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