Home
Class 12
PHYSICS
Given a battery, how would you connect ...

Given a battery, how would you connect two capaitors, it series or in paralllel for them to store the greater (a) total charge (b) total energy ?

Text Solution

Verified by Experts

Total charge `q = CV` and total energy `U = (1)/(2) CV^(2)`
Now, V is constant and `C_(p) gt C_(s)`,
therefore, parallel combination is required for strong greater charge and greater energy.
Promotional Banner

Similar Questions

Explore conceptually related problems

Two capcitors, 3 muF and 4 muF, are individually charged across a 6 V battery. After being disconnected from the battery, they are connected together with the negative plate of one attached to the positive plate of the other. What is the final total energy stored ?

A battery of 10V is connected to a capacitor of capacity 0. lF . The battery is now removed and this capacitor is connected to a second uncharged capacitor. If the charges are distributed equally on these two capacitors, find the total energy stored in the two capacitors. Find the ratio of final energy to initial energy stored in capacitors.

Rahul connected the two wires in series and observe that total resistance increases. Justify.

The figure below shows a battery of emf epsilon connected to an inductor L and resistance R in series. If the switch is closed at t=0, then the total charge that flows from the battery in time constant of the circuit is

You have two identical capacitors and an extermal potential source. a. Compare the total energy stored in capaciton when they are connected to the applied potential in series and in parallel. b. Compare the maximum amount of charge stored in each case. c. Energy storage in a capacitor can be limited by the maximum electric field between the plates. What is the ratio of the electric field for the series for parallel combinations?

A capacitor of capacitance C_(1) is charged to a potential V_(1) while another capacitor of capacitance C_(2) is charged to a potential difference V_(2) . The capacitors are now disconnected from their respective charging batteries and connected in parallel to each other . (a) Find the total energy stored in the two capacitors before they are connected. (b) Find the total energy stored in the parallel combination of the two capacitors. (c ) Explain the reason for the difference of energy in parallel combination in comparison to the total energy before they are connected.

The enrgy of a charged capacitor is U. Another identical capacitor is connected parallel to the first capacitor, after disconnecting the battery. The total energy of the system of these capacitors will be

A capacitor is charged using a battery and energy stored is U. After disconnecting the battery, another uncharged capacitor of same capacitance is connected in parallel to the first capacitor. Then loss of energy is equal to