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Two capacitors of capacitance of 6 muF a...

Two capacitors of capacitance of `6 muF and 12 muF` are connected in series with a battery. The voltage across the `6 muF` capacitor is 2V. Compute the total battery voltage.

Text Solution

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In series, charge on `C_(1)` = charge on `C_(2)`
`6xx2 = 12 xx V_(2)`
`V_(2) = (12)/(12) = 1 vo l t`
`:.` Battery voltage `V = V_(1) + V_(2) = 2 + 1 = 3V`
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