Three capacitors `C_(1), C_(2) and C_(3)` are connected to a 6 V battery, as shown in Fig. Find the charges on the three capcitors.

Explanation

The given arrangement is equivalent to the arrangement shown in Fig. clearly, `C_(2) and C_(3)` are in parallel.
Their equivalent capacitance is
`C' = C_(2) + C_(3) = 5+5 = 10 muF`

Now `C_(1)` and C' form a series combination as shown in Fig. Their equivalent capacitance is `C = (C_(1)C')/(C_(1) + C') = (10xx10)/(10+10) = 5 muF` Charge drawn from the battery
`q = CV = 5 muF xx 6V = 30 muF`
Charge on parallel combination of `C_(2) and C_(3)`
`= q = 30 muC`
As `C_(2) and C_(3)` are equal, so charge is shared equally by two capacitors
Charge on `C_(2)` = Charge on `C_(3) = (30)/(2) = 15 muC`
Charge on `C_(1) = 30 muC`