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Careful measurement of the electric fi...

Careful measurement of the electric field at the surface of a black box inidicates that the net outward flux through the surface of the box is `8.0xx10^(3) Nm^(2)//C` (a) what is the net charge inside the box ? (b) If the net outward flux through the surface of the box were zero, could you conclude that there were no charges inside the box ? Why or why not?

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To solve the problem, we will use Gauss's Law, which states that the net electric flux (Φ) through a closed surface is equal to the charge (Q) enclosed by that surface divided by the permittivity of free space (ε₀). The formula is given by: \[ \Phi = \frac{Q_{\text{enclosed}}}{\varepsilon_0} \] Where: - Φ is the electric flux, ...
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