Home
Class 12
PHYSICS
Suppose that the particle in Q.33 is an...

Suppose that the particle in Q.33 is an electron projected with velocity `v_(x) = 2.0xx10^(6) ms^(-1)`. If E between the plates separated by `0.5 cm is 9.1xx10^(2) N//C`, where will the electron strike the upper plate ? `(|e| = 1.6xx10^(-19) C,m_(e) = 9.1xx10^(-31) kg).`

Text Solution

Verified by Experts

Here, `v_(x) = 2.0xx10^(6) ms^(-1), E = 9.1xx10^(2) N//C, d = 0.5 cm = 5xx10^(-3)m`
`q = e = 1.6xx10^(-19) C, m_(e) = 9.1xx10^(-31) kg`
The electron will strike the upper plate at its other end at `x = L` is soon as its deflection
`y = (d)/(2) = (5xx10^(-3))/(2) = 2.5xx10^(-3) m`
From `y = (qE L^(2))/(2 mv_(x)^(2))`
`L = sqrt((2my)/(qE)) xx v_(x) = sqrt((2xx9.1xx10^(-31)xx2.5xx10^(-3))/(1.6xx10^(-19)xx9.1xx10^(2))) xx2xx10^(6) = 1.12xx10^(-2) m = 1.12 cm`
Hence the electron will strike the upper plate at its other end, if length of plate is 1.12 cm.
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATICS

    PRADEEP|Exercise LONG ANSWER QUESTIONS|8 Videos

  • ELECTROSTATICS

    PRADEEP|Exercise VALUE BASED QUESTIONS|7 Videos

  • ELECTROSTATICS

    PRADEEP|Exercise NCERT QUESTIONS|13 Videos

  • ELECTRONIC DEVICES

    PRADEEP|Exercise Fill in the Blanks|1 Videos

  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Competition Focus (Multiple Choice Questions)|2 Videos

Similar Questions

Explore conceptually related problems

Calculate the gyro magnetic ratio of electron (given 1.6 xx10^(-19) C, m_r=9.1xx10^(-3) kg )

De - Broglie wavelength of an electron accelerated by a voltage of 50 V is close to (|e|=1.6xx10^(-19)C,m_(e)=9.1xx10^(-31))

The Velocity of electrons accelerated bt potential difference of 1xx10^(4) V (the charge of the electron is 1.6xx10^(-19) C and mass is 9.11xx10^(-31) kg) is

An electron is projected as in fig. at a speed of 6 x 10^(6)ms^(-1) at an angle of 45^(@) E=2000Vm^(-1) directed upward d=3cm and 1=10cm. Will the electron strike either of the plates?

In a chamber, a uniform magnetic field of 6.5 G (1 G = 10^(-4)T) is maintained. An electron is shot into the field with a speed of 4.8 xx 10^(6) ms^(-1) normal to the field. Explain why the path of the electron is a circle. Determine the radius of the circular orbit. (e = 1.6 xx 10^(-19) C, m_(e) = 9.1 xx 10^(-31) kg) .

If de Broglie wavelength of an electron is 0.5467 Å, find the kinetic energy of electron in eV. Given h=6.6xx10^(-34) Js , e= 1.6xx10^(-19) C, m_e=9.11xx10^(-31) kg.

The mass of an electron is 9.1xx10^(-31) kg and velocity is 2.99xx10^(10) cm s^(-1) . The wavelenth of the electron will be