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A regular hexagon of side 10 cm has a ch...

A regular hexagon of side 10 cm has a charge `5 muC` at each of its vertices. Calculate the potential at the center of the hexagon.

Text Solution

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In fig, 0 is center of hexagon ABXDEFA of each side 10 cm. As is clear from the figure, OAB,OBC etc, are equilaterial triangles. Therefore,
`OA = OB = OC = OD = OE = OF`
`= r = 10 cm, 10^(-1)m`
As potential is scaler, therefore potential at O is
`V = 6 xx (q)/(4pi in_(0) r) = (9xx10^(9)xx6xx5xx10^(-6))/(10^(-1)) = 2.7xx10^(6) V`
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