Two charged conducting spheres of radill a and b are connected to eachother by a wire. What is the ratio of electric fields at the surface of two spheres ? Use the result obtained to explain why charge density on the sharp and pointed ends of a conducter is higher than on its fatter portions ?

Explanation

To find the ratio of electric fields at the surface of two connected conducting spheres, we can follow these steps:

### Step 1: Understand the Concept of Electric Field
The electric field \( E \) at the surface of a charged conducting sphere is given by the formula:
\[ E = \frac{Q}{4\pi \epsilon_0 r^2} \]
where \( Q \) is the charge on the sphere, \( \epsilon_0 \) is the permittivity of free space, and \( r \) is the radius of the sphere.
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