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An arbitrary surface encloses a dipole. ...

An arbitrary surface encloses a dipole. What is the electric flux through this surface ?

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As net charge on a dipole is `(-q +q) = 0`, therefore, when an arbitrary surface encloses a dipole as per Gauss's theorem, electric flux through the surface
`oint vec(E). vec(ds) = (q)/(in_(0)) = zero`.
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