Estimate the number of free electrons in 36g of water and the negative charge possessed by them. Given : Avogadro's number `= 6.023xx10^(23)` and molecular weight of water = 18.

Answer

`1.92736xx10^(6)C`

Explanation

Here, no of molecules in 36g of water
A water `(H_(2) O)` molecule is made up of two hydrogen atoms and one oxygen atom. Each hydrogen atom contains 8 electrons. So, each molecule of water has 10 electrons.
No. of free electrons in 36g of water
`= 12.046xx10^(23)xx10 = 12.0426xx10^(24)`
Negative charge, q =n e
`= 12.046xx10^(24)xx1.6xx10^(-19)C`
`= 1.92736xx10^(6)C`