Calculate the total positive (or negative) charge on a 3.11 g copper penny. Given Avogadro's number `=6.023xx10^(23)(g^(-1)) mol^(-1),`, Given Avogadro's number and atomic mass= `63.5 g`.

Answer

`+-1.37xx10^(5)C`

Explanation

Number of atoms in penny
`n' = (6.023xx10^(23))/(63.5) xx3.11`
As each atom consists 29 protons and 29 electrons
`:. "Total positive"//"negative"` charge on the penny
`q = +- n e = +- n' xx 29e`
`= +- (6.023xx10^(23)xx3.11)/(63.5) xx29xx1.6xx10^(-19) C`
`= +-1.37xx10^(5)C`