A charged ball of mass `8.4xx10^(16) kg` is found to remain suspended in a uniform electric field of `2xx10^(4) Vm^(-1)`. Calculate the charge on the ball. Given `g = 10 m//s^(2)`

Answer

`4.2xx10^(-19) C`

Explanation

As `qE = mg :. q = (mg)/(E) = (8.4xx10^(-16)xx10)/(2xx10^(4))`
`= 4.2xx10^(-19)C`