Two charges `+30 muC and -30 muC` are placed 1cm apart. Calculate electric field at a point on the axial line at a distance of 20cm from the centre of dipole.

Answer

`6.25xx10^(5) N//C`

Explanation

As `r gt gt a`, so `E = (2 vec(p))/(4pi in_(0) r^(3))`
`= (9xx10^(9)xx2xx30xx10^(-6)xx10^(-2))/((20xx10^(-2))^(3)) = 6.25xx10^(5) N//C`