Two charges `+ 10 muC` and `+ 20 muC` are placed at a. separation of 2 cm. Find the electric potential due to the. pair at the middle point of the line joining the two charges.

Answer

27 MV

Explanation

Electric potential at middle point `V = V_(1) + V_(2)`
`V = (1)/(4pi in_(0)) [(q_(1))/(r_(1)) + (q_(2))/(r_(2))]`
`= 9xx10^(9) [(10xx10^(6))/(0.01) + (20xx10^(-6))/(0.01)]`
`= 27xx10^(6) V = 27MV`