A rectangular surface of sides `10 cm and 15 cm` is palaced inside a uniform electric field fo `25 Vm^(-1)`, such that normal to the surface makes an angle of `60^(@)` with the direction of electric field. Find the flux of electric field through the rectangular surface.

Answer

`1.8xx10^(-1) Nm^(2) C^(-1)`

Explanation

Here, `E = 25 Vm^(-1)`,
`s = 10xx15 cm^(2) = 150xx10^(-4) m^(2)`
`theta = 60^(@) , phi = ?`
`phi = Es cos theta = 25xx150xx10^(-4) cos 60^(@)`
`phi = 1.8xx10^(-1) Nm^(2) C^(-1)`