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An infinite line charge produces a field...

An infinite line charge produces a field of `9xx10^(4) NC^(-1)` at a distance of `4 cm`. Calculate the linear charge density.

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To solve the problem of finding the linear charge density (λ) of an infinite line charge that produces an electric field (E) of \(9 \times 10^4 \, \text{N/C}\) at a distance (r) of \(4 \, \text{cm}\), we can follow these steps: ### Step 1: Write the formula for the electric field due to an infinite line charge. The electric field (E) produced by an infinite line charge is given by the formula: \[ E = \frac{\lambda}{2 \pi \epsilon_0 r} \] where: - \(E\) is the electric field, - \(\lambda\) is the linear charge density, - \(\epsilon_0\) is the permittivity of free space (\(\epsilon_0 \approx 8.85 \times 10^{-12} \, \text{C}^2/\text{N m}^2\)), - \(r\) is the distance from the line charge. ### Step 2: Rearrange the formula to solve for linear charge density (λ). To find \(\lambda\), we rearrange the formula: \[ \lambda = 2 \pi \epsilon_0 E r \] ### Step 3: Convert the distance from centimeters to meters. The distance \(r\) is given as \(4 \, \text{cm}\). We need to convert this to meters: \[ r = 4 \, \text{cm} = 4 \times 10^{-2} \, \text{m} \] ### Step 4: Substitute the known values into the formula. Now we can substitute the values into the rearranged formula: - \(E = 9 \times 10^4 \, \text{N/C}\) - \(\epsilon_0 = 8.85 \times 10^{-12} \, \text{C}^2/\text{N m}^2\) - \(r = 4 \times 10^{-2} \, \text{m}\) Substituting these values: \[ \lambda = 2 \pi (8.85 \times 10^{-12}) (9 \times 10^4) (4 \times 10^{-2}) \] ### Step 5: Calculate the value of λ. Calculating this step-by-step: 1. Calculate \(2 \pi \approx 6.2832\). 2. Calculate \(8.85 \times 10^{-12} \times 9 \times 10^4 \approx 7.965 \times 10^{-7}\). 3. Multiply by \(4 \times 10^{-2}\): \[ \lambda \approx 6.2832 \times 7.965 \times 10^{-7} \times 4 \times 10^{-2} \] \[ \lambda \approx 2 \times 10^{-7} \, \text{C/m} \] ### Final Answer: The linear charge density \(\lambda\) is approximately: \[ \lambda \approx 2 \times 10^{-7} \, \text{C/m} \] ---

To solve the problem of finding the linear charge density (λ) of an infinite line charge that produces an electric field (E) of \(9 \times 10^4 \, \text{N/C}\) at a distance (r) of \(4 \, \text{cm}\), we can follow these steps: ### Step 1: Write the formula for the electric field due to an infinite line charge. The electric field (E) produced by an infinite line charge is given by the formula: \[ E = \frac{\lambda}{2 \pi \epsilon_0 r} \] where: ...
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Knowledge Check

  • An infinite line charge produces a field of 19xx10^(4) NC^(-1) at a distance of 5cm. Calculate the linear charge density.

    A
    `1.5 muC//m`
    B
    `1.0 muC//m`
    C
    0
    D
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    B
    `10^(-6)C//m`
    C
    `10^(-7)C//m`
    D
    `10^(-8)C//m`
  • An infinite line charge produce a field of 7.182xx10^(8)NC^(-1) at a distance of 2 cm. The linear charge density is

    A
    `7.27xx10^(-4)Cm^(-1)`
    B
    `7.98xx10^(-4)Cm^(-1)`
    C
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    D
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