A charged spherical conductor has a surface density of `0.07 C cm^(-2)`. When the charge is increased by `4.4 C`, the surface density changes to `0.084 C cm^(-2)`. Find the initial charge and capacitance of the spherical conductor.

Answer

`5xx10^(3) V`

Explanation

Here, `V = ? q = 5 muC = 5xx10^(-6)C`
`C = 1 nF = 10^(-9) F`
`V = (q)/(C ) = (5xx10^(-6))/(10^(-9)) = 5xx10^(3) V`