Find out the potentail difference across the plates of `1 mu F` capacitors in Fig.

Answer

`3.82 V`

Explanation

In Fig.
`C_(P_(1)) = 3+6 = 9 muF`
`(1)/(C_(S_(1))) = (1)/(4) + (1)/(9) = (13)/(36) C_(S_(1)) = (36)/(13) muF`
`C_(P_(2)) = (36)/(13) + 12 = (36+156)/(13) = (192)/(13) muF`
`(1)/(C_(s)) = (1)/(2) + (1)/(2) + (13)/(192) = (192+96+13)/(192) = (301)/(192)`
`C_(s) = (192)/(301) muF Q = C_(s) V = (192)/(301) xx 6 muC`
`V_(1) = (Q)/(C_(1)) = (192xx6)/(301xx1) = 3.82` volt