A network of four each of `12 mu F` capacitance is connected to a `500 V` apply as shown in Fig.

(a) Equivalent capacitance of the network.
(b) Charge on each capacitor.

Answer

(a) `16 muF` (b) `q_(1) = q_(2) = q_(3) = 2000 muC, q_(4) = 6000 muC`

Explanation

Here, `C_(1), C_(2), C_(3)` are in series.
`C_(123) = (12 muF)/(3) = 4 muF`
As `C_(4)` is in parallel with this combination,
`:. C_(eq) = 4+12 = 16 muF`
`q_(1) = q_(2) = q_(3) = C_(123) V = 4 muF xx 500 = 2000 muC`
`q_(4) = C_(4) V = 12 muF xx 500 V = 6000 muC`